When 5V potential difference is applied across a wire of length 0.1 m, the drift speed of electrons is 2.5 × 10 –4 ms –1 . If the electron density in the wire is 8 × 10 28 m –3 , the resistivity of the material is close to
Text Solution
Verified by ExpertsThe correct answer is:
D
v d = 2.5 × 10 –4 m/s
n = 8 × 10 28 /m 3
I = neAv d
= neAv d
ρ = 
= 
= 1.6 × 10 –5 Ω Ω m
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